Y=-0.25x^2+3

Solution for Y=-0.25x^2+3 equation:

=-0.25Y^2+3

We move all terms to the left:

-(-0.25Y^2+3)=0

We get rid of parentheses

0.25Y^2-3=0

a = 0.25; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·0.25·(-3)
Δ = 3
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{3}}{2*0.25}=\frac{0-\sqrt{3}}{0.5}
=-\frac{\sqrt{}}{0.5}
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{3}}{2*0.25}=\frac{0+\sqrt{3}}{0.5}
=\frac{\sqrt{}}{0.5}
$